Function bevy_internal::utils::petgraph::algo::floyd_warshall::floyd_warshall
source · pub fn floyd_warshall<G, F, K>(
graph: G,
edge_cost: F
) -> Result<HashMap<(<G as GraphBase>::NodeId, <G as GraphBase>::NodeId), K>, NegativeCycle>where
G: NodeCompactIndexable + IntoEdgeReferences + IntoNodeIdentifiers + GraphProp,
<G as GraphBase>::NodeId: Eq + Hash,
F: FnMut(<G as IntoEdgeReferences>::EdgeRef) -> K,
K: BoundedMeasure + Copy,
Expand description
[Generic] Floyd–Warshall algorithm is an algorithm for all pairs shortest path problem
Compute shortest paths in a weighted graph with positive or negative edge weights (but with no negative cycles)
Arguments
graph
: graph with no negative cycleedge_cost
: closure that returns cost of a particular edge
Returns
Ok
: (if graph contains no negative cycle) a hashmap containing all pairs shortest pathsErr
: if graph contains negative cycle.
Examples
use petgraph::{prelude::*, Graph, Directed};
use petgraph::algo::floyd_warshall;
use std::collections::HashMap;
let mut graph: Graph<(), (), Directed> = Graph::new();
let a = graph.add_node(());
let b = graph.add_node(());
let c = graph.add_node(());
let d = graph.add_node(());
graph.extend_with_edges(&[
(a, b),
(a, c),
(a, d),
(b, c),
(b, d),
(c, d)
]);
let weight_map: HashMap<(NodeIndex, NodeIndex), i32> = [
((a, a), 0), ((a, b), 1), ((a, c), 4), ((a, d), 10),
((b, b), 0), ((b, c), 2), ((b, d), 2),
((c, c), 0), ((c, d), 2)
].iter().cloned().collect();
// ----- b --------
// | ^ | 2
// | 1 | 4 v
// 2 | a ------> c
// | 10 | | 2
// | v v
// ---> d <-------
let inf = std::i32::MAX;
let expected_res: HashMap<(NodeIndex, NodeIndex), i32> = [
((a, a), 0), ((a, b), 1), ((a, c), 3), ((a, d), 3),
((b, a), inf), ((b, b), 0), ((b, c), 2), ((b, d), 2),
((c, a), inf), ((c, b), inf), ((c, c), 0), ((c, d), 2),
((d, a), inf), ((d, b), inf), ((d, c), inf), ((d, d), 0),
].iter().cloned().collect();
let res = floyd_warshall(&graph, |edge| {
if let Some(weight) = weight_map.get(&(edge.source(), edge.target())) {
*weight
} else {
inf
}
}).unwrap();
let nodes = [a, b, c, d];
for node1 in &nodes {
for node2 in &nodes {
assert_eq!(res.get(&(*node1, *node2)).unwrap(), expected_res.get(&(*node1, *node2)).unwrap());
}
}